'How to test the IBM WebSphere Message Broker in JMeter
I have a scenario where i need to test the IBM WebSphere Message Broker(JMS request) in JMeter.
Currently i have below details with me. Using this below information, may i know how to create this script in JMeter.
Example : Queue manager name : ACE config SVR/TCP/localhost(1414), Queue name : DNB LT.SRVC, XML Payload
Also, Manual testing team is using the RHF utility to perform this testing.
Solution 1:[1]
I believe the best option is going for JSR223 Sampler and custom Groovy code.
Download the relevant version of com.ibm.mq.allclient and drop it to "lib" folder of your JMeter installation (or other location which is in JMeter Classpath)
Restart JMeter to pick the .jar up
Add JSR223 Sampler to your Test plan
Put the following code into "Script" area
import com.ibm.msg.client.jms.JmsConnectionFactory import com.ibm.msg.client.jms.JmsFactoryFactory import com.ibm.msg.client.wmq.WMQConstants import javax.jms.Session def hostName = "127.0.0.1" def hostPort = 1414 def channelName = "DEV.APP.SVRCONN" def queueManagerName = "QM1" def queueName = "DNB LT.SRVC" def ff = JmsFactoryFactory.getInstance(WMQConstants.WMQ_PROVIDER) def cf = ff.createConnectionFactory() cf.setStringProperty(WMQConstants.WMQ_HOST_NAME, hostName) cf.setIntProperty(WMQConstants.WMQ_PORT, hostPort) cf.setStringProperty(WMQConstants.WMQ_CHANNEL, channelName) cf.setIntProperty(WMQConstants.WMQ_CONNECTION_MODE, WMQConstants.WMQ_CM_CLIENT) cf.setStringProperty(WMQConstants.WMQ_QUEUE_MANAGER, queueManagerName) def conn = cf.createConnection("app", "test") def sess = conn.createSession(false, Session.AUTO_ACKNOWLEDGE) def destination = sess.createQueue(queueName) conn.start() def producer = sess.createProducer(destination) def payload = 'Your XML payload here' def msg = sess.createTextMessage(payload) producer.send(msg) producer.close() conn.close() sess.close()Run your test and the message should be sent
More information: IBM MQ testing with JMeter - Learn How
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Dmitri T |
