'How to print the objects specific member using only object name? [duplicate]

string var = "Hello";
cout << var << endl;

We get the result using only the object, without the help of a member variable. I want to implement a class that will work like string. For example:

class Test {
public:
    int x = 3;
};

Test var2;
cout << var2 << endl;

How can I get implement the class so the cout line prints the value of x without referring to it?

c++outputoperator-overloading


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