'How to pass a procedure as a parameter in Racket Language?

(define (remove (lambda) lst)
  (if (empty? lst)
      0
      (if ((lambda(car lst) = 'false))
          (cons (car lst '() lambda (cdr lst)))
          (lambda (cdr lst)))))

This piece of code is used to check if numbers in list pass the test called lambda, and return a list without the passed element. So command like (remove (lambda (x) (= x 0)) (list 0 1 2 3)) would able to pass lambda function as a parameter and use it inside the remove function. How should I do that?

parameterslispracket


Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source

Related Questions