'How to open my flutter app by clicking a url
I'm working on a flutter app, and now I need to be able to open my app whenever a URL with a certain pattern is clicked.
In other words, I'd like to have that option from a clicked URL saying "Which app do you want to use to open this link"
and from the shown apps to open this link I want mine to be in there
Is it possible? How can I do this?
Also, I need to say I have done this from Android Studio - Java, but never in flutter/dart, I am a newbie around flutter
Solution 1:[1]
I have found the solution, this link is going to give you everything you need for deep linking in flutter:
https://pub.dev/packages/uni_links
Documentation/Installation
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Devck - DC |