'how to make android suggest my app for opening location sent from whatsapp?
I have added a deep link in manifest
i added this host "maps.google.com" that i found from whatsapp location but that s not working
I tried
<intent-filter android:autoVerify="true">
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE"/>
<data
android:host="maps.google.com"
android:pathPrefix="/maps"
android:scheme="http" />
<data
android:host="maps.google.com"
android:pathPrefix="/maps"
android:scheme="https" />
</intent-filter>
and just like other deep links defined in manifest i expect android suggest the app in disambiguation dialog ...can anyone help me?
Solution 1:[1]
You must implement a Geo Service Activity
The Geo Service Activity catches android.intent.action.VIEW from online mapservices. Here is a working example:
<!-- get geo-location from online mapservices (google, yandex, here, openstreetmap) -->
<intent-filter>
<data android:scheme="http" />
<data android:scheme="https" />
<data android:host="maps.google.com" />
<data android:host="maps.google.de" />
<data android:host="www.openstreetmap.org" />
<data android:host="openstreetmap.org" />
<data android:host="maps.yandex.ru" />
<data android:host="maps.yandex.com" />
<data android:host="here.com" />
<data android:host="www.here.com" />
<data android:host="share.here.com" />
<data android:host="goto.here.com" />
<data android:host="go.here.com" />
<data android:host="wego.here.com" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
</intent-filter>
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
Intent intent = getIntent();
if (intent != null) {
Object uri = intent.getData();
message.append(MessageFormat.format("Received action:{0}\n - data:{1}\n", intent.getAction(), uri));
if (uri != null) {
// parse uri
.... process uri
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | k3b |
