'How to load image from photos using new PHPicker in iOS programmatically?
I want to select an image from photos using new PHPickerViewController and I want to open PHPicker directly when my controller is load.
Like this

import UIKit
class ViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
// TODO: - Here I want PhotoPicker
}
}
Solution 1:[1]
you can call this method openPHPicker() when ever you want to place your PHPicker.
You can use this code also. for opening new PHPicker.
For More Knowledge about PHPicker in WWDC21 PHPicker WWDC20 Video and PHPicker WWDC21 Video
WWDC PHPicker Notes PHPicker Notes
import Photos
import PhotosUI
// MARK: - PHPicker Configurations (PHPickerViewControllerDelegate)
extension ViewController: PHPickerViewControllerDelegate {
func picker(_ picker: PHPickerViewController, didFinishPicking results: [PHPickerResult]) {
picker.dismiss(animated: true, completion: .none)
results.forEach { result in
result.itemProvider.loadObject(ofClass: UIImage.self) { reading, error in
guard let image = reading as? UIImage, error == nil else { return }
DispatchQueue.main.async {
self.profilePictureOutlet.image = image
// TODO: - Here you get UIImage
}
result.itemProvider.loadFileRepresentation(forTypeIdentifier: "public.image") { [weak self] url, _ in
// TODO: - Here You Get The URL
}
}
}
}
/// call this method for `PHPicker`
func openPHPicker() {
var phPickerConfig = PHPickerConfiguration(photoLibrary: .shared())
phPickerConfig.selectionLimit = 1
phPickerConfig.filter = PHPickerFilter.any(of: [.images, .livePhotos])
let phPickerVC = PHPickerViewController(configuration: phPickerConfig)
phPickerVC.delegate = self
present(phPickerVC, animated: true)
}
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Chandan |
