'How to implement the field decimal(5,2) in EntityFrameworkCore 1.0 rc2?

How to implement the field decimal(5,2) in EntityFrameworkCore 1.0 rc2 ?

HasPrecision seems to be not available anymore?

c++sharpentity-framework-core


Solution 1:[1]

I'm seeing some examples like this:

 entityBuilder.Property(r => r.TotalScore)
            .HasColumnType("decimal(5,2)")
            .IsRequired(true);

and the code to support this is here, so hopefully this is supported in the version you're using:

https://github.com/aspnet/EntityFramework/blob/f416dd9a71a5a6a69715b4ba40a37e6f9da751ef/src/Microsoft.EntityFrameworkCore.Relational/Metadata/Internal/RelationalPropertyBuilderAnnotations.cs

Solution 2:[2]

You can add extensions for that like this:

public static class SqlServerModelBuilderExtensions
{
    public static PropertyBuilder<decimal?> HasPrecision(this PropertyBuilder<decimal?> builder, int precision, int scale)
    {
        return builder.HasColumnType($"decimal({precision},{scale})");
    }

    public static PropertyBuilder<decimal> HasPrecision(this PropertyBuilder<decimal> builder, int precision, int scale)
    {
        return builder.HasColumnType($"decimal({precision},{scale})");
    }
}

Solution 3:[3]

JFYI, if somedoby is stil comming to this question (like I did)

In the current version of EF Core (2.2) there is also the Data Annotation way to do this:

public class SomeEFModelClass
{
    [Column(TypeName = "decimal(5,2)")]
    public decimal TotalScore{ get; set; }
}

Link to docs: https://docs.microsoft.com/en-us/ef/core/modeling/relational/data-types

Solution 4:[4]

Since EF Core 5 you can use this:

modelBuilder.Entity<Payment>().Property(b => b.Amount).HasPrecision(5, 2);

Sources

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Source: Stack Overflow

Solution Source
Solution 1 AaronLS
Solution 2 Andrés Robinet
Solution 3 Tolbxela
Solution 4

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