'How to give a cell containing with 'ISREF' a default value in Google Sheets
I am trying to use a formula that uses INDEX function. In order to generalize for all the lines that sometimes may contain information from another sheet and sometimes they may not.
That's why I get an ISREF error within the cells because the corresponding cells in the other sheet can't be referenced.
I want to display a default value instead of the ISREF error message. I tried using ISREF function itself within an IF condition but it doesn't work on the same cell. It only references another cell because it is a cell checking function and it doesn't check the output of a formula.
I tried also ISERROR function but it didn't work also. Here's a snippet of the formula that I am putting within my cell:'
INDEX(Plagesuivi; $Q203; 9)
- Plagesuivi is a named range
- $Q203 contains the row number (that I fetch dynamically and correctly)
- 9 is the column number
P.S. The indexing is working fine with cells that do appear is the named range: Plagesuivi
Solution 1:[1]
After trial and error the best way to avoid all sorts of errors is:
= IF($Q203=""; 0; IFERROR(INDEX(Plagesuivi; $Q203; 9); 0))
IFERRORchecks for all sorts of unpredictable errrors it is a safe-guard against unpredicted cases where it takes 0 by default.IFin the second case checks whether the referencing content of Q203 is empty or not, in case it is empty the cell takes 0 by default else it gets the output of the false case formula.
Solution 2:[2]
I would go with iferror() like this:
=iferror(INDEX(Plagesuivi;$Q203;9);0)
Or replace the 0 with ""
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | haddagart |
| Solution 2 | Solar Mike |
