How to get the latest and oldest record in mongoose.js (or just the timespan between them)

Question

Basic problem

I have a bunch of records and I need to get latest (most recent) and the oldest (least recent).

When googling I found this topic where I saw a couple of queries:

// option 1
Tweet.findOne({}, [], { $orderby : { 'created_at' : -1 } }, function(err, post) {
  console.log( post );
});
// option 2
Tweet.find({}, [], {sort:[['arrival',-1]]}, function(err, post) {
  console.log( post );
});

Unfortunatly they both error:

TypeError: Invalid select() argument. Must be a string or object.

The link also has this one:

Tweet.find().sort('_id','descending').limit(15).find(function(err, post) {
  console.log( post );
});

and that one errors:

TypeError: Invalid sort() argument. Must be a string or object.

So how can I get those records?

Timespan

Even more ideally I just want the difference in time (seconds?) between the oldest and the newest record, but I have no clue on how to start making a query like that.

This is the schema:

var Tweet = new Schema({
    body: String
  , fid: { type: String, index: { unique: true } }
  , username: { type: String, index: true }
  , userid: Number
  , created_at: Date
  , source: String
});

I'm pretty sure I have the most recent version of mongoDB and mongoose.

EDIT

This is how I calc the timespan based on the answer provided by JohnnyHK:

var calcDays = function( cb ) {
  var getOldest = function( cb ) {
    Tweet.findOne({}, {}, { sort: { 'created_at' : 1 } }, function(err, post) {
      cb( null, post.created_at.getTime() );
    });
  }
    , getNewest = function( cb ) {
    Tweet.findOne({}, {}, { sort: { 'created_at' : -1 } }, function(err, post) {
      cb( null, post.created_at.getTime() );
    });
  }

  async.parallel({ 
    oldest: getOldest
  , newest: getNewest
  }
    , function( err, results ) {
      var days = ( results.newest - results.oldest ) / 1000 / 60 / 60 / 24;
      // days = Math.round( days );
      cb( null, days );
    }
  );
}

Answer 1

Fast and Simple - One Line Solution

Get 10 latest documents

MySchema.find().sort({ _id: -1 }).limit(10)

Get 10 oldest documents

MySchema.find().sort({ _id: 1 }).limit(10)

In case you want sorting based on some other property i.e. createdAt and get the oldest or latest. It is similar to the above query.

MySchema.find().sort({ createdAt: -1 }).limit(10)  // 10 latest docs
MySchema.find().sort({ createdAt: 1 }).limit(10) // 10 oldest docs

Answer 2

for version ~3.8 mongoose

to find the last entry

model.findOne().sort({ field: 'asc', _id: -1 }).limit(1)

or using

model.findOne().sort({ field: -_id }).limit(1)

Answer 3

collectionName.findOne().sort({$natural: -1}).limit(1).exec(function(err, res){
    if(err){
        console.log(err);
    }
    else{
        console.log(res);
    }
}

This will give you the last document recorded on the database. Just follow the same concept.

Answer 4

await Model.find().sort({$natural:-1}).limit(1); //for the latest record
await Model.find().sort({$natural:1}).limit(1); //for the oldest record

This one works for me. using mongodb natural order https://docs.mongodb.com/manual/reference/operator/meta/natural/

Answer 5

We have method called sort using that we can able to get first element(old document) which means 1 for sort field or last element(new document) which means -1 for sort field of collection.

Answer 6

Here is the answer with async - await

const olderDoc: any = await Model.findOne().sort({ createdAt: 1 }).lean().exec()
console.log('olderDoc', olderDoc)

const newerDoc: any = await Model.findOne().sort({ createdAt: -1 }).lean().exec()
console.log('newerDoc', newerDoc)

Answer 7

The best way is to have an async function like that:

async function findLastElement () {
    return await Mymodel.findOne().sort('-_id');
}

this way you get the last element and you ensure reusability.