'How to get cookie value

Creating cookie

session_start();
$params = session_get_cookie_params();    
setcookie(session_name('USERNAME'),'HAMZA',1,
      isset($params['path']),
      isset($params['domain']),
      isset($params['secure']),
      isset($params['httponly']));

session_regenerate_id(true);
echo "COOKIE IS CREATED SUCCESSFULLY !";

Now fetching cookie value

session_start();
$NAME=$_COOKIE['USERNAME'];
echo $_COOKIE["USERNAME"];

if(isset($NAME))
{
      if($NAME=='USERNAME')
      {
          echo "success";
      }
      else
     {
          echo "error";       
     }    
 }

Please Help Me !

Result

Why they create Auto random Value Like: u8omuum6c9pkngrg4843b3q9m3). But i want to get my Original COOKIE value Which is "HAMZA" ?????

phpcookies


Solution 1:[1]

This is the PHP syntax for cookie creation:

setcookie($name, $value, $expires, $path, $domain, $secure, $httponly);

The first variable is your cookie name, which you can use to read the value like this:

$_COOKIE['YOUR COOKIE NAME'];

Note: Like other headers, cookies must be sent before any output from your script. This requires that you place calls to this function prior to any output, including <html> and any whitespace.
Also note that dots and spaces (./ ) in cookie names are replaced with underscores (_).

Documentation: setcookie(), $_COOKIE[]

Solution 2:[2]

Function session_name will give you hash which atucally is you session identifier. It seems like you want to get USERNAME stored in session, don't you? In that case you should use $_SESSION array.

Code example:

setcookie($_SESSION['USERNAME'],'HAMZA',1,
      isset($params['path']),
      isset($params['domain']),
      isset($params['secure']),
      isset($params['httponly']));

And you can get it like this: 

$myCookie = $_COOKIE[$_SESSION['USERNAME']];

But from your second code it's not quite clear what you want to get. If you want to ask for $_COOKIE['USERNAME'] and get 'HAMZA' then you should set it like this: 

setcookie('USERNAME','HAMZA',1,
      isset($params['path']),
      isset($params['domain']),
      isset($params['secure']),
      isset($params['httponly']));

And when you retrieve it $NAME=='USERNAME' makes no sense, because it will be like $NAME=='HAMZA': 

$NAME=$_COOKIE['USERNAME'];
echo $_COOKIE['USERNAME'];

if(isset($NAME))
{
      if($NAME=='HAMZA')
      {
          echo "success";
      }
      else
     {
          echo "error";       
     }    
 }

Solution 3:[3]

try this one ...

<?
   $yummy = json_decode(json_encode($_COOKIE));

   if(isset($yummy->yourvar)) echo $yummy->yourvar;
?>

Why using encode and decode ?, it use to convert type Array to JSON originally type $_COOKIE is Array

Solution 4:[4]

try this one ...

setcookie($cookie_name, $cookie_value, 1800, "/");

change expires time with:

setcookie($cookie_name, $cookie_value, time()+ 1800, "/");

and get

$_COOKIE[$cookie_name];

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 isherwood
Solution 2 Djengobarm
Solution 3
Solution 4

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