'How to generate UL Li list from string array using jquery?

I have string array like

'United States', 'Canada', 'Argentina', 'Armenia', 'Aruba', 'Australia', 'Austria', 'Azerbaijan', 'Bahamas', 'Bangladesh', 'Belarus', 'Belgium'**, ... etc.

I want create a dynamic list from string array like below:-

<ul class="mylist" style="z-index: 1; top: 474px; left: 228px; display: none; width: 324px;" > 
  <li class="ui-menu-item" role="menuitem">
     <a class="ui-all" tabindex="-1">
         United States
    </a>
  </li>
  <li class="ui-menu-item" role="menuitem">
     <a class="ui-all" tabindex="-1">
         Canada
    </a>
  </li>
  <li> .... </li>
   .....
</ul>

How is it possible using jQuery?

jqueryjquery-uijquery-selectorsjavascript-framework


Solution 1:[1]

With ES6 you can write this:

const countries = ['United States', 'Canada', 'Argentina', 'Armenia'];

const $ul = $('<ul>', { class: "mylist" }).append(
  countries.map(country => 
    $("<li>").append($("<a>").text(country))
  )
);

Solution 2:[2]

An even better approach using the array's join method

const countries = ['United States', 'Canada', 'Argentina', 'Armenia'];
const list = '<ul class="myList"><li class="ui-menu-item" role="menuitem"><a class="ui-all" tabindex="-1">' + countries.join('</a></li><li class="ui-menu-item" role="menuitem"><a class="ui-all" tabindex="-1">') + '</a></li></ul>';

Solution 3:[3]

var countries = ['United States', 'Canada', 'Argentina', 'Armenia'];
var cList = $('ul.mylist')
$.each(countries, function(i) {
    var li = $('<li/>')
        .addClass('ui-menu-item')
        .attr('role', 'menuitem')
        .appendTo(cList);
    var a = $('<a/>')
        .addClass('ui-all')
        .text( this )
        .appendTo(li);
});

Solution 4:[4]

    <script type="text/javascript" >
        function aa()
        {
            var YourArray = ['United States', 'Canada', 'Argentina', 'Armenia'];
            var ObjUl = $('<ul></ul>');
            for (i = 0; i < YourArray.length; i++)
            {
                var Objli = $('<li></li>');
                var Obja = $('<a></a>');

                ObjUl.addClass("ui-menu-item");
                ObjUl.attr("role", "menuitem");

                Obja.addClass("ui-all");
                Obja.attr("tabindex", "-1");

                Obja.text(YourArray[i]);
                Objli.append(Obja);

                ObjUl.append(Objli);
            }
            $('.DivSai').append(ObjUl);
        }
    </script>
</head>
<body onload="aa()">
    <form id="form1" runat="server">
    <div class="DivSai" >

    </div>
    </form>
</body>

Solution 5:[5]

Other variation of Abhishek Bhalani: You can use Array.map() instead of $.each()

var items = ['United States', 'Canada', 'Argentina', 'Armenia'];
var cList = $('ul.mylist');
items.map( (item,i ) => {
      var li = $('<li/>')
        .addClass('ui-menu-item')
        .attr('role', 'menuitem')
        .appendTo(cList);
      $('<a class="ui-all">'+ i + ': ' + item.name + '<a/>')
        .appendTo(li);
    });

Solution 6:[6]

It's possible without jQuery too! :)

let countries = ['United States', 'Canada', 'Argentina', 'Armenia', 'Aruba'];

// The <ul> that we will add <li> elements to:
let myList = document.querySelector('ul.mylist');

// Loop over the Array of country names:
countries.forEach(function(value, index, array) {
  // Create an <li> element:
  let li = document.createElement('li');

  // Give it the desired classes & attributes:
  li.classList.add('ui-menu-item');
  li.setAttribute('role', 'menuitem');

  // Now create an <a> element:
  let a = document.createElement('a');

  // Give it the desired classes & attributes:
  a.classList.add('ui-all');
  a.tabIndex = -1;
  a.innerText = value; //  <--- the country name from our Array
  a.href = "#"

  // Now add the <a> to the <li>, and add the <li> to the <ul>
  li.appendChild(a);
  myList.appendChild(li);
});
<ul class="mylist"></ul>

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1
Solution 2
Solution 3 Mike Thomsen
Solution 4
Solution 5
Solution 6 Josh Withee

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