'How to fill date range gaps Oracle SQL
With a given dataset:
WITH ranges AS (
select to_date('01.01.2021 00:00:00','DD.MM.YYYY hh24:mi:ss') date_from,
to_date('31.03.2021 00:00:00','DD.MM.YYYY hh24:mi:ss') date_to
from dual
union
select to_date('27.03.2021 00:00:00','DD.MM.YYYY hh24:mi:ss') date_from,
to_date('27.04.2021 00:00:00','DD.MM.YYYY hh24:mi:ss') date_to
from dual
union
select to_date('01.05.2021 00:00:00','DD.MM.YYYY hh24:mi:ss') date_from,
to_date('31.12.2021 00:00:00','DD.MM.YYYY hh24:mi:ss') date_to
from dual
)
SELECT * FROM ranges;
How to find the gap 28.04.2021-30.04.2021.? Also consider that there can be multiple gaps in between and ranges can overlap.
Any suggestion?
Solution 1:[1]
You are modeling date ranges incorrectly; an interval ending at midnight on 02-14-2021, for example, should not include 02-14-2021. In your model it does.
This leads to unnecessary complications in all the queries you write against your model. In the solution below I need to add 1 to end dates first, do all the processing, and then subtract 1 at the end.
with
ranges (date_from, date_to) as (
select to_date('01.01.2021 00:00:00','DD.MM.YYYY hh24:mi:ss'),
to_date('31.03.2021 00:00:00','DD.MM.YYYY hh24:mi:ss')
from dual
union all
select to_date('27.03.2021 00:00:00','DD.MM.YYYY hh24:mi:ss'),
to_date('27.04.2021 00:00:00','DD.MM.YYYY hh24:mi:ss')
from dual
union all
select to_date('01.05.2021 00:00:00','DD.MM.YYYY hh24:mi:ss'),
to_date('31.12.2021 00:00:00','DD.MM.YYYY hh24:mi:ss')
from dual
)
select first_missing, last_missing - 1 as last_missing
from (
select dt as first_missing,
lead(df) over (order by dt) as last_missing
from (select date_from, date_to + 1 as date_to from ranges)
match_recognize(
order by date_from
measures first(date_from) as df, max(date_to) as dt
pattern (a* b)
define a as max(date_to) >= next (date_from)
)
)
where last_missing is not null
;
FIRST_MISSING LAST_MISSING
------------------- -------------------
28.04.2021 00:00:00 30.04.2021 00:00:00
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | mathguy |
