'How to do double-indirection with jq variables?
How to construct a name of a variable from data and access that variable?
For example it should somehow give the content of the alpha-file:
jq '$.var"-file"' --slurpfile alpha-file <(echo 0) --slurpfile beta-file <(echo 1) <<<'{"var": "alpha"}'
It should output:
[
  0
]
Solution 1:[1]
Named arguments are also available to the jq program as $ARGS.named.
So there is a dictionary to extract variables by a string name from:
jq '$ARGS.named["\(.var)-file"]' --slurpfile alpha-file <(echo 0) --slurpfile beta-file <(echo 1) <<<'{"var": "alpha"}'
outputs
[
  0
]
Solution 2:[2]
You could use getpath like this:
jq --slurpfile alphaFile <(echo 0) --slurpfile betaFile <(echo 1) '
   .var as $ab | {alpha: $alphaFile, beta: $betaFile} | getpath([$ab])' <<< '{"var": "alpha"}'
Better yet:
jq --slurpfile alpha <(echo 0) --slurpfile beta <(echo 1) '
   .var as $ab | {$alpha, $beta} | getpath([$ab])' <<< '{"var": "alpha"}'
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source | 
|---|---|
| Solution 1 | Velkan | 
| Solution 2 | 
