How to add url keyword parameter in list action of drf?

Question

I want to generate url like /users/{role_id}/,this means show all users that role_id=={role_id} my code like this

class OutWorkAllocationView(viewsets.GenericViewSet):
    """

    """
    filter_backends = (BaseFilterBackend, filters.OrderingFilter)
    authentication_classes = (JWTAuthentication,)
    serializer_class = someSerializer
    lookup_field = 'role_id'

    def get_queryset(self):
        role_id = self.kwargs['id']
        user_ids = UserRoleRef.objects.filter(role_id=role_id).values_list('user_id', flat=True)
        return User.objects.filter(id__in=user_ids)

    @action(methods=['get'], detail=True)
    def list_allocation(self):

        queryset = self.filter_queryset(self.get_queryset())

        page = self.paginate_queryset(queryset)
        if page is not None:
            serializer = self.get_serializer(page, many=True)
            return self.get_paginated_response(serializer.data)

        serializer = self.get_serializer(queryset, many=True)
        return Response(serializer.data)