How Should I Define an Array of Pointers to Functions in C++?

Question

I'm trying to make an array of functions so I can call functions from the array with an index. I can't seem to figure out the parentheses, asterisks and brackets to create this array of functions. Here is what I have:

void Game::getPawnMoves(int position, bool color, Move ** moveList) {
    ...
}

typedef void (*GetMoveFunction) (int, bool, Move **);
void Game::getLegalMoves(Move ** moveList) {
    GetMoveFunction functions[] = 
    {
        getPawnMoves, 
        getKnightMoves, 
        getBishopMoves,
        getRookMoves,
        getQueenMoves,
        getKingMoves
    };
    ...
}

All of the getPawnMoves, getKnightMoves, and the rest all have the same arguments and all return void. Move is just a struct with two chars and an enum. In this case, if you'd like to try compiling it, you could replace Move ** with int **.

The error I'm getting when I compile is:

Game.cpp:443:5: error: cannot convert ‘Game::getPawnMoves’ from type 
‘void (Game::)(int, bool, Move**) {aka void (Game::)(int, bool, Move_t**)}’ to 
type ‘GetMoveFunction {aka void (*)(int, bool, Move_t**)}’

So for some reason the compiler thinks that GetMoveFunction is void * instead of void, but if I change the typedef to

typedef void (GetMoveFunction) (int, bool, Move **);

I get the error:

Game.cpp:435:28: error: declaration of ‘functions’ as array of functions
  GetMoveFunction functions[] = 

I'm honestly super stuck on this one. Thanks so much for your help!