How does this code for creating multiple variables within a dictionary work? [duplicate]

Question

I've been trying to find a way to create variables from within a for loop without needing to know in advance how many variables I will need to create. I've run into examples such as:

a_dictionary = {}
for number in range(1,4):
    a_dictionary["key%s" %number] = "abc"

print(a_dictionary)
{'key1': 'abc', 'key2': 'abc', 'key3': 'abc'}

Another I have seen is

d={}
for x in range(1,10):
    d["string{0}".format(x)]="Variable1"

print(d)
{'string1': 'Variable1', 'string2': 'Variable1','string3': 'Variable1', 'string4': 'Variable1', 'string5':'Variable1', 'string6': 'Variable1', 'string7': 'Variable1','string8': 'Variable1', 'string9': 'Variable1'}

My question is, how does this work, and is there a way to do something similar, like global variables without the need for a dictionary? For example, to do something like

random_list = [23,67,12,93,5,420]
for i in range(0,6):
    variable_i = random_list[i]
    print(variable_i)

23
67
12
93
5
420

to achieve the same thing as a manual assignment such as

variable_0 = 23
variable_1 = 67
variable_2 = 12
variable_3 = 93
variable_4 = 5
variable_5 = 420

Answer 1

The module namespace is a dictionary and you can get it via globals(). Using f-strings (the newest way to build strings from variables) and the enumerate function instead of range, you could

>>> random_list = [23,67,12,93,5,420]
>>> for i, val in enumerate(random_list):
...     globals()[f"variable_{i}"] = val
... 
>>> variable_0
23

The for can be replaced by using the dictionary's "update" method

globals().update((f"variable_{i}", val) for i, val in enumerate(random_list))