How do you return multiple values from a typescript function

Question

I'd like a Typescript function to return multiple values. How do I do this? Also - how do I declare the types?

For example I want to achieve something like this:

let [text, value] = ReturnTwoValues("someinputstring")

Answer 1

Function definition:

public ReturnTwoValues(someInput: string): [string, boolean] {
    const text = "hello"
    const value = true
    return [text, value]
}

Caller:

let [text, value] = ReturnTwoValues("someinputstring")

Answer 2

public ReturnTwoValues(someInput: string): {text:string, value:boolean} {
    const text = "hello"
    const value = true
    return {text, value}
}

let {text, value} = ReturnTwoValues("some irrelevant string");

console.log(text) //output hello
console.log(value) // output value

Answer 3

Of course, since a function returns one value, then the only way to return more than one value is to wrap them together in some object; as others have noted in the comments, an array is a kind of object. However, you don't have to create a new object for this, so technically what you're asking for is possible. Here's a solution which uses the function itself as the return value, so it meets the criterion of not creating an object when the function is called.

interface Foo {
    x: string,
    y: number,
    (): Foo
}

const foo = (() => {
    foo.x = 'bar';
    foo.y = 1;
    return foo;
}) as Foo;

let { x, y } = foo();
console.log(x); // bar
console.log(y); // 1

Playground Link

I don't recommend actually doing this, though; since it doesn't return a fresh object each time, it can lead to bugs if you retain a reference to the return value and expect its properties to stay the same.