'How do I replace only part of an image source?
Is there a way to use jQuery to change a part of an image's source URL?
I'm working on a page that has a number of image elements that are all programmatically generated (but I'm not able to access the source code that generates them). And they all share the same class.
Let's say I have the following HTML:
<img src="https://cdn.example.com/pictures/01.jpg" class="photo">
<img src="https://cdn.example.com/pictures/02.jpg" class="photo">
<img src="https://cdn.example.com/pictures/03.jpg" class="photo">
<img src="https://cdn.example.com/pictures/04.jpg" class="photo">
Simple enough. But now, what if I want to point them all to a different directory? Like: /images/
So far, I've tried a few things, including this bit of jQuery, but nothing's done the trick so far:
$("img.photo").attr("src").replace("pictures","images");
That feels like it should do it because it's targeting images with that class -> then the "src" attribute -> and telling it to replace "pictures" with "images."
But I'm extremely new to using jQuery, so I'd appreciate some help.
What am I missing here? Any advice?
UPDATE: Huge thanks to those who provided answers and explanations — I really appreciate you helping a beginner!
Solution 1:[1]
Your code snippet won't work, because that's grabbing the src attribute of the first image, and changing it, but never setting the result as the new src on the <img> elements.
Try this
$("img.photo").each((index, img) => {
img.src = img.src.replace("pictures","images");
});
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Alexandros Katechis |
