'How do I make it so that ctx is not of type 'interaction' (nextcord slash commands)?
I'm trying to create a music bot using nextcord slash commands and interactions. The command isn't fully finished yet, as I am having trouble getting it to even join the voice channel. I don't exactly know how interactions work yet but I'm assuming it's a similar concept as ctx. Below is my music.py cog:
import nextcord
from nextcord.ext import commands
from nextcord import Interaction
class Music(commands.Cog):
def __init__(self, client):
self.client = client
guild_ids = ["Guild Ids Go Here"]
#slash commands go under here
@nextcord.slash_command(name="play", description="plays music in vc", guild_ids = guild_ids)
async def play(self, interaction : Interaction, query: str):
channel = interaction.author.voice.channel #ERROR IS HERE
try:
await channel.connect()
await interaction.response.send_message("The bot has joined vc.")
except:
await interaction.response.send_message("Failed to find voice channel.")
def setup(client):
client.add_cog(Music(client))
I'm getting an error that says "'Interaction' object has no attribute 'author'. It occurs on line 15 in 'play' when it says 'channel = interaction.author.voice.channel'. I think this means that this isn't the right way to go about getting the author's voice channel. If this is the case, is there a better, working method?
Solution 1:[1]
In nextcord interaction, message author is
interaction.user, channel isinteraction.channel.You also can send interaction message by
interaction.sendinstead ofinteraction.response.send_message. It's much shorter and easier to read.If you want to send a normal message without using interaction, try
interaction.channel.send. It's similar toctx.channel.sendin application command
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Dharman |
