How do I grab last number in a string in PHP?

Question

How can I get 23 instead of 1 for $lastnum1?

$text = "1 out of 23";
$lastnum1 = $this->getEval(eregi_replace("[^* out of]", '', $text));

Answer 1

you could do:

$text = "1 out of 23";
if(preg_match_all('/\d+/', $text, $numbers))
    $lastnum = end($numbers[0]);

Note that $numbers[0] contains array of strings that matched full pattern,
and $numbers[1] contains array of strings enclosed by tags.

Answer 2

$text = "1 out of 23";
$ex = explode(' ',$text);
$last = end($ex);

and if you whant to be sure that that last is a number

if (is_numeric(end($ex))) {
    $last = end($ex);
} 

Answer 3

Another way to do it:

$text = "1 out of 23";
preg_match('/(\d+)\D*$/', $text, $m);
$lastnum = $m[1];

This will match last number from the string even if it is followed by non digit.

Answer 4

Use preg_match to extract the values into $matches:

preg_match("/([0-9]+) out of ([0-9]+)/", $text, $matches);

Answer 5

$text = '1 out of 23';
preg_match('/\d+ out of (\d+)/', $text, $matches);
$lastnum1 = $matches[1];

Answer 6

If the format will be the same, why not explode the string and convert the last one?

<?php
$text = "1 out of 23";
$words = explode(" ",$text);
$lastnum = (int)array_pop($words);