How do I filter view controller by type?

Question

This is my simple function:

func popTo<T: UIViewController>(type: T.Type, from context: UINavigationController?) {
    let mytype = type
    guard let controller = context?.viewControllers.first(where: { $0 is T }) else {
        return
    }
    print(mytype) //1
    print(context?.viewControllers) //2
    print(controller) //3
    context?.popToViewController(controller, animated: true)
}

After I put a breakpoint and print out the following lines, I get console output:

PLZ.GroupViewController //1

▿ Optional<Array<UIViewController>> //2
  ▿ some : 5 elements
    ▿ 0 : <PLZ.GroupsViewController: 0x11dd68660>
    ▿ 1 : <PLZ.GroupViewController: 0x11f415c70>
    ▿ 2 : <PLZ.ProductViewController: 0x11f619d00>
    ▿ 3 : <PLZ.ConfirmViewController: 0x11f538cd0>
    ▿ 4 : <PLZ.ConfirmationViewController: 0x11f53e330>

<PLZ.GroupsViewController: 0x11dd68660> //3

Why it returns GroupsViewController when it should GroupViewController?

How do I call that function?

if let type = viewModel.returnControllerType {
    print(type) //4
    self?.router.popTo(type: type, from: self?.navigationController)
} 

PLZ.GroupViewController //4

returnControllerType is defined:

let returnControllerType: UIViewController.Type?

Answer 1

The simplest solution ever is:

func popTo<T: UIViewController>(type: T.Type, from context: UINavigationController?) {
    guard let controller = context?.viewControllers.first(where: { $0.isKind(of: type) }) else {
        return
    }
    context?.popToViewController(controller, animated: true)
}