'How do I calculate number of given weekday between range using Moment JS?
How do I find out how many of a given weekday (ex: Tuesdays) are in a date range using Moment JS and jQuery?
I can find the number of days using Difference: http://momentjs.com/docs/#/displaying/difference/
And I know the start and end date, so I feel like it should be possible?
Example: How many Tuesdays are there between March 1st and March 25th?
Solution 1:[1]
If you're trying to find the number of weekdays W (e.g. Monday, Tuesday, …) between the two dates N and M, you can:
- Find the next occurance N' of W after N.
- Find the number of days between N' and M.
- If N' is after M, there are no W's between. Otherwise, the number of W days should then be 1 + floor((M-N)/7).
function getWeekdaysBetweenDates(firstDate, secondDate, dayOfWeek) {
var MILISECONDS_IN_DAY = 86400000;
function getNextDayOfWeek(date, dayOfWeek) {
date.setDate(date.getDate() + (7 + dayOfWeek - date.getDay()) % 7);
return date;
}
firstDate = getNextDayOfWeek(firstDate, dayOfWeek);
if (firstDate > secondDate) {
return 0;
}
return 1 + Math.floor(((secondDate - firstDate) / MILISECONDS_IN_DAY) / 7);
}
var firstDate = new Date("March 1, 2015");
var secondDate = new Date("March 25, 2015");
console.log(getWeekdaysBetweenDates(firstDate, secondDate, 2));
// 4
Solution 2:[2]
https://github.com/andruhon/moment-weekday-calc does what you need. It calculates specific weekdays in the range, with option to exclude particular days (say public holidays)
Usage:
moment().isoWeekdayCalc({
rangeStart: '1 Apr 2015',
rangeEnd: '31 Mar 2016',
weekdays: [1,2,3,4,5], //weekdays Mon to Fri
exclusions: ['6 Apr 2015','7 Apr 2015'] //public holidays
}) //returns 260 (260 workdays excluding two public holidays)
Solution 3:[3]
let dayno = [0, 1, 2, 3, 4, 5, 6]
for (let i = 0; i < dayno.length; i++) {
let start = moment('2022-1-01')
let end = moment('2022-1-31')
getweek(start, end, dayno[i])
}
var dataArray = []
const getweek = (start, end, dayno) => {
var arr = []
let tmp = start.clone().day(dayno)
if (tmp.isAfter(start, 'd')) {
arr.push(tmp.format('YYYY-MM-DD'))
}
while (tmp.isBefore(end)) {
tmp.add(7, 'days')
if (tmp.format('M') == start.format('M')) {
arr.push(tmp.format('YYYY-MM-DD'))
}
}
const dow = moment(start).startOf('month').day()
if (dow + 1 == dayno + 1) {
var obj = {
name: dayno + 1,
value: arr.length + 1,
}
} else {
var obj = {
name: dayno + 1,
value: arr.length,
}
}
dataArray.push(obj)
}
Solution 4:[4]
if you are like me with a mind that get confused on maths:
var startDate = moment().startOf('month');
var endDate = moment().endOf('month');
var aDate = moment(startDate).day('Sunday');
var weekDays = 0;
while (aDate.isSameOrBefore(endDate)) {
if (aDate.isSameOrAfter(startDate) && aDate.isSameOrBefore(endDate))
weekDays++;
aWeekDayDate.add(1, 'week');
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | kba |
| Solution 2 | Andrew Kondratev |
| Solution 3 | Ayush Gupta |
| Solution 4 |
