'How can I make user input case insensitive in an HTML Form in Apps Script?
I have made a custom function on Google Sheets that allows the user to see how much they have spent on an expense.
The HTML sidebar:
Here is the JavaScript function:
function perCentBrand(brand){
var sh = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
var values = sh.getRange(2,1,sh.getLastRow()-1,sh.getLastColumn()).getValues();
var total = 0;
var sum = 0;
values.forEach(function(row){
total+=row[1];
if (row[6]==brand){sum+=row[1]}
})
var val = "You spent a total of " + sum + " on " + brand + " out of " + total + " ." + " Additionally, " + (sum/total)*100 + "%" + " of your income has been spent on " + brand;
var ui = SpreadsheetApp.getUi();
ui.alert(val)
}
And here is the HTML form code:
<form onsubmit="runFunc()">
<input class = "u-full-width " id="brand" type = "text" placeholder="Enter brand name">
<div class="u-full-width" style="display:flex; justify-content: center">
<button type="submit" class="button-primary">Submit</button>
</div>
</form>
I have read about the toLowerCase() and the toUpperCase() methods but I am unsure if these should be included to make the user input case insensitive.
Thanks in advance.
Solution 1:[1]
function perCentBrand(brand){
var sh = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
var values = sh.getRange(2,1,sh.getLastRow()-1,sh.getLastColumn()).getValues();
var total = 0;
var sum = 0;
values.forEach(function(row){
total+=row[1];
if (row[6].toLowerCase() == brand.toLowerCase()){sum+=row[1]}
})
var val = "You spent a total of " + sum + " on " + brand + " out of " + total + " ." + " Additionally, " + (sum/total)*100 + "%" + " of your income has been spent on " + brand;
var ui = SpreadsheetApp.getUi();
ui.alert(val)
}
Solution 2:[2]
I'm assuming you mean "make user input case insensitive" regarding your if-statement, so I would control for case there if (row[6].toLowerCase()==brand.toLowerCase()){sum+=row[1]}.
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Cooper |
| Solution 2 | user1599011 |


