How can I make a direct PHONE CALL in Flutter

Question

I need to make a direct Phone Call in flutter but it's just opening the Phone app dialer.
No direct phone call is made.

In fact, I also tried with url_launcher package for this task but am getting the same result.

    _launchURL() async {
    SimplePermissions.requestPermission(Permission.CallPhone)
        .then((state) async {
      if (state == PermissionStatus.authorized) {
        String a = Uri.encodeFull("#");
        String url = 'tel:*123' + a;
        if (await canLaunch(url)) {
          await launch(url);
        } else {
          throw 'Could not launch $url';
        }
      }
    });}

Has anyone solved this before?

Answer 1

You need to use URL encoding for special character.

Like this:

launch("tel:" + Uri.encodeComponent('*123#'));

Answer 2

I made a plugin called flutter_phone_direct_caller exactly for this purpose.

You can use it like this:

import 'package:flutter/material.dart';
import 'package:flutter_phone_direct_caller/flutter_phone_direct_caller.dart';

void main() {
  runApp(Scaffold(
    body: Center(
      child: RaisedButton(
        onPressed: _callNumber,
        child: Text('Call Number'),
      ),
    ),
  ));
}

_callNumber() async{
  const number = '08592119XXXX'; //set the number here
  bool res = await FlutterPhoneDirectCaller.callNumber(number);
}

Hopefully it can help someone.

Answer 3

Add these packages to your dependencies:

android_intent_plus: ^2.0.0
permission_handler: ^8.1.4+2

Import them in your .dart file:

import 'package:android_intent_plus/android_intent.dart';
import 'package:permission_handler/permission_handler.dart';

Request for phone call permission in your main() function:

void main() async {
  WidgetsFlutterBinding.ensureInitialized();
  await Permission.phone.request();
  runApp(const MyApp());
}

And finally you can make direct phone calls like this:

AndroidIntent intent = const AndroidIntent(
  action: 'android.intent.action.CALL',
  data: 'tel:2125551212',
);
await intent.launch();