How Can I Make a conditional with return in a .map without get out of main function?

Question

My objective is create this object:

{
  name: string,
  birthday: date
}

by this array:

const dataArray = [
 {
  "id": "name",
  "type": "string"
 },
 {
  "id": "birthday",
  "type": "date"
 }
]

So, I create a .map of the array, like this:

const inputsValues = {};

dataArray.map(item => {
  if(item.type === "date"){
    inputsValues[item.id] = new Date(item.value);
    return; // this line is the problem
  }

  inputsValues[item.id] = item.value;
});

Is there a option to make a return in this function without use else?

Answer 1

const data = [
  {id: "name", type: "string", value: "John"},
  {id: "birthday", type: "date", value: "02.02.22"},
  {id: "holiday", type: "date", value: "03.03.33"}
]

const inputsValues = data
  // the "return" function - filters all non "date" items
  .filter(item => item.type != "date")
  // the map + inputsValue combination in one function
  .reduce((values, item) => ({[item.id]: item.value, ...values}), {})
  
console.log(inputsValues)

Answer 2

const dataArray = [{
    "id": "name",
    "type": "string"
  },
  {
    "id": "birthday",
    "type": "date"
  }

]
console.log(
  dataArray.reduce((acc, curr) => {
    acc[curr.id] = curr.type;
    return acc;
  }, {})
);

Answer 3

Is this what you're trying to achieve?

const dataArray = [
 { "id": "name", "type": "string" },
 { "id": "birthday", "type": "date" }
]

console.log(dataArray.reduce((acc, obj, i) => {
  const key = obj.id;
  const value = obj.type;
  acc[key] = value;
  return acc;
}, {}))