'How can I check if a set of functions all return non null, in a single expression?
Suppose I have three functions foo, bar, baz, all of which return nullable types.
fun foo(): Int? = 1
fun bar(): Int? = 2
fun baz(): Int? = 3
I want to call them, and if all them returns non-null, I want to compute a value from their return values.
I could do this with statements, like this:
val x = foo()
val y = bar()
val z = baz()
val result = if (x != null && y != null && z != null) x + y + z else null
However, I don't like the fact that I have to declare 3 extra variables that I can still access afterwards. By having 3 extra statements like this, it also means that I cannot use expression-bodied functions, if I were writing a function that returns result.
If I use lets instead:
val result = foo()?.let { x ->
bar()?.let { y ->
baz()?.let { z ->
x + y + z
}
}
}
This creates a deep nesting. If it were only one function, this would have been fine, but with 3 functions or more, this makes my intention of "call these three functions, if they are all non null, add them together" rather unclear.
How can I write this in a way that clearly conveys my intention, but also making it a single expression?
Solution 1:[1]
You could filter out all null-values and only apply an operation on the list, if it did not shrink in size, e.g.:
fun sumIfNoneNull(values: List<Int?>): Int? = values
.filterNotNull()
.takeIf { it.size == values.size }
?.sum()
One may generalize this further, e.g.:
fun <T, R> List<T>.foldIfNoneNull(
initial: R,
operation: (acc: R, T) -> R
): R? = this
.filterNotNull()
.takeIf { nonNullList -> nonNullList.size == this.size }
?.fold(initial, operation)
You may use this like any other fold, e.g.:
listOf(foo(), bar(), baz()).foldIfNoneNull(0) { acc, cur -> acc + cur }
Solution 2:[2]
val result = listOf(foo(), bar(), baz())
.reduce { acc, i ->
when {
acc == null || i == null -> null
else -> acc + i
}
}
Or as function:
fun <T> apply(operation: (T, T) -> T, vararg values: T?): T? {
return values
.reduce { acc, i ->
when {
acc == null || i == null -> null
else -> operation(acc, i)
}
}
}
val result = apply({ x, y -> x + y }, foo(), bar(), baz())
Sources
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Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | |
| Solution 2 |
