'How access embedded control in style from style trigger
I want to create style that can change embedded in him controls, like here I want to change "Source" of "ImageIco" but I get errors. Is it possible to make it inside style? Because all examples what I see use additional code or writing additional code in window itself.
Problematic part:
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter TargetName="IcoImage" Property="Source" Value="{DynamicResource InfoIco.Red}"/>
</Trigger>
<Trigger Property="IsMouseOver" Value="False">
<Setter TargetName="IcoImage" Property="Source" Value="{DynamicResource InfoIco.White}"/>
</Trigger>
</Style.Triggers>
All style code:
<Style BasedOn="{StaticResource {x:Type Button}}"
TargetType="{x:Type Button}"
x:Key="RedsInfoButton">
<Style.Setters>
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="Button">
<Grid Background="{TemplateBinding Background}"
HorizontalAlignment="Stretch"
VerticalAlignment="Stretch"
Width="{TemplateBinding Width}"
Height="{TemplateBinding Height}">
<Image Name="IcoImage"
Source="{DynamicResource InfoIco.White}"/>
</Grid>
</ControlTemplate>
</Setter.Value>
</Setter>
<Setter Property="Background" Value="Transparent"/>
<Setter Property="BorderThickness" Value="0"/>
</Style.Setters>
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter TargetName="IcoImage" Property="Source" Value="{DynamicResource InfoIco.Red}"/>
</Trigger>
<Trigger Property="IsMouseOver" Value="False">
<Setter TargetName="IcoImage" Property="Source" Value="{DynamicResource InfoIco.White}"/>
</Trigger>
</Style.Triggers>
</Style>
<BitmapImage x:Key="InfoIco.White" UriSource="/WPFDesign/Data/Images/InfoWhite.ico"/>
<BitmapImage x:Key="InfoIco.Red" UriSource="/WPFDesign/Data/Images/InfoRed.ico"/>
Sources
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Source: Stack Overflow
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