GZip every file separately

Question

How can we GZip every file separately?

I don't want to have all of the files in a big tar.

Answer 1

Easy and very fast answer that will use all your CPU cores in parallel:

parallel gzip ::: *

GNU Parallel is a fantastic tool that should be used far more in this world where CPUs are only getting more cores rather than more speed. There are loads of examples that we would all do well to take 10 minutes to read... here

Answer 2

After seven years, this highly upvoted comment still doesn't have its own full-fledged answer, so I'm promoting it now:

gzip -r .

This has two advantages over the currently accepted answer: it works recursively if there are any subdirectories, and it won't fail from Argument list too long if the number of files is very large.

Answer 3

If you want to gzip every file recursively, you could use find piped to xargs:

$ find . -type f -print0 | xargs -0r gzip

Answer 4

Try a loop

$ for file in *; do gzip "$file"; done

Answer 5

Or, if you have pigz (gzip utility that parallelizes compression over multiple processors and cores)

pigz *

Answer 6

The following command can run multiple times inside a directory (without "already has .gz suffix" warnings) to gzip whatever is not already gzipped.

find . -maxdepth 1 -type f ! -name '*.gz' -exec gzip "{}" \;

A more useful example of utilizing find is when you want to gzip rolling logs. E.g. you want every day or every month to gzip rolled logs but not current logs.

# Considering that current logs end in .log and 
# rolled logs end in .log.[yyyy-mm-dd] or .log.[number]
find . -maxdepth 1 -type f ! -name '*.gz' ! -name '*.log' -exec gzip "{}" \;

Answer 7

fyi, this will help to overwrite if an existing gz file along with creating few gz file if it is not present:

find . -type f | grep "in case any specific" | grep -E -v "*.gz$" | xargs -n1 -P8 sh -c 'yes | gzip --force --best -f $0'