Getting All Elements In An Array (Javascript)

Question

I am trying to check if a string contains certain words which I had stored in an array... however I'm new to JS, so I don't exactly know how to check all of the elements inside the Array.

Here is an Example:

const fruits = ["apple", "banana", "orange"]

I am actually checking if someone sends swearwords in a chat.

if(message.content.includes(fruits)){executed code}

However my issue is when I check for fruits it does anything but when I check for a specific element in the array like fruits[0] //returns apple it will actually check for that... So my issue / question is how do I check the string for all of the elements in the array not just apples.

Answer 1

Your usage of includes is wrong.

From MDN:

The includes() method determines whether an array includes a certain value among its entries, returning true or false as appropriate.

arr.includes(valueToFind[, fromIndex])

const fruits = ["apple", "banana", "orange"];
const swearWord = "orange";

// execute is available
if (fruits.includes(swearWord))
  console.log("Swear word exists.");
else 
  console.log("Swear word doesn't exist.");

To check the otherway, if string contains the array's swearword:

const fruits = ["apple", "banana", "orange"];
const swearWord = "this contains a swear word. orange is the swear word";

// execute is available
if (checkForSwearWord())
  console.log("Swear word exists.");
else
  console.log("Swear word doesn't exist.");

function checkForSwearWord() {
  for (const fruit of fruits) 
    if (swearWord.includes(fruit)) return true;
  return false;
}

Answer 2

You got it the other way around. You have to use .includes on the data array to check if the array includes the word you are looking for.

const fruits = ["apple", "banana", "orange"]
console.log(fruits.includes("banana"))
console.log(fruits.includes("something not in the array"))

Answer 3

I would use an intersection here. Just in case you don't know what that is ...

An intersection is the elements that two arrays share in common.

For example

swearWords = ["f***", "s***"];
messageWords = ["I", "am", "angry...", "f***", "and", "s***"];
let intersection = messageWords.filter(x => swearWords.includes(x));
console.log(intersection) //-> ["f***", "s***"]

Answer 4

Reverse it:

if(fruits.includes(message.content)){executed code};

Docs for Array.includes. You are using the String.includes method. You can, alternatively, also use the indexOf method.

Answer 5

try this .

fruits.forEach(fruit => {
    if (message.content.includes(fruit)) {
        console.log('true')
        return;
    }
    console.log('false')
})

Hope this help .

Answer 6

you can try to use the Array some method

const fruits = ["apple", "banana", "orange"]
const containsFruit = fruit => message.content.includes(fruit);

if(fruits.some(containsFruit)) { executed code }

containsFruit is a function that will return true if a fruit is found in the message.content

fruits.some(containsFruit) will be true if any item in the array is found to be contained in the message.content

Answer 7

The other way to do this is with a regular expression.

For a large message string, this may be quicker than calling .includes() in a loop vs an array (which needs to loop over the entire string each time). However this should be tested.

let fruits = ["apple", "banana", "orange"]
let fruits_regex = fruits.map(f => f.replace(/(?=\W)/g, '\\')).join('|');  // escape any special chars
// fruits_regex == "apple|banana|orange"

let message = 'apple sauce with oranges';
let matches = [ ...message.matchAll(fruit_regex) ]
// [
//   ["apple",  index:  0, input: "apple sauce with oranges", groups: undefined]
//   ["orange", index: 17, input: "apple sauce with oranges", groups: undefined]
// ]

Answer 8

const fruits = ["apple", "banana", "orange"]
if(fruits.some(x => message.content.includes(x))){
  /* executed code */
};