Get ip address (internet dynamic ip)

Question

I try to get internet dynamic IP address with the following code when mobile connection is provided. getHostAddress return 10.13.x.x ssid internal host address. But I want to get as 178.240.x.x dynamic internet IP address. Thanks in advance.

for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements();) {
    InetAddress inetAddress = enumIpAddr.nextElement();
    if (!inetAddress.isLoopbackAddress()) {
        networkIpAdress = inetAddress.getHostAddress().toString();
    }
}

Answer 1

Use this URL to get your public IP address:

https://ident.me

Note: You might have both IPv4 and IPv6 addresses, in which case you can use https://v4.ident.me and https://v6.ident.me respectively.

The documentation is at https://api.ident.me.

Answer 2

If your device is connected with wifi then

 WifiManager wifiManager = (WifiManager) getSystemService(WIFI_SERVICE);
 WifiInfo wifiInfo = wifiManager.getConnectionInfo();
 int ipAddress = wifiInfo.getIpAddress();

An Android device can both be connected via WiFi, and 3G, which obviously has different IPs. The IP address on 3G will also change every time it reconnects.

Answer 3

I resolved my question with following code.

    HttpClient httpclient = new DefaultHttpClient();
    HttpGet httpget = new HttpGet("http://ip2country.sourceforge.net/ip2c.php?format=JSON");
    HttpResponse response;
    response = httpclient.execute(httpget);
    HttpEntity entity = response.getEntity();
    entity.getContentLength();
    JSONObject json_data = new JSONObject(EntityUtils.toString(entity));
    String networkIpAdress = json_data.getString("ip");