'Get everything after and before certain character in SQL Server
I got the following entry in my database:
images/test.jpg
I want to trim the entry so I get: test
So basically, I want everything after / and before .
How can I solve it?
Solution 1:[1]
use the following function
left(@test, charindex('/', @test) - 1)
Solution 2:[2]
Before
SELECT SUBSTRING(ParentBGBU,0,CHARINDEX('/',ParentBGBU,0)) FROM dbo.tblHCMMaster;
After
SELECT SUBSTRING(ParentBGBU,CHARINDEX('-',ParentBGBU)+1,LEN(ParentBGBU)) FROM dbo.tblHCMMaster
Solution 3:[3]
----select characters before / including /
select SUBSTRING ('abcde/wxyz',0,CHARINDEX('/','abcde/wxyz')+1)
--select characters after / including /
select SUBSTRING('abcde/wxyz',CHARINDEX('/','abcde/wxyz'),LEN('abcde/wxyz'))
Solution 4:[4]
declare @T table
(
Col varchar(20)
)
insert into @T
Select 'images/test1.jpg'
union all
Select 'images/test2.png'
union all
Select 'images/test3.jpg'
union all
Select 'images/test4.jpeg'
union all
Select 'images/test5.jpeg'
Select substring( LEFT(Col,charindex('.',Col)-1),charindex('/',Col)+1,len(LEFT(Col,charindex('.',Col)-1))-1 )
from @T
Solution 5:[5]
I have made a method which is much more general :
so :
DECLARE @a NVARCHAR(MAX)='images/test.jpg';
--Touch here
DECLARE @keysValueToSearch NVARCHAR(4000) = '/'
DECLARE @untilThisCharAppears NVARCHAR(4000) = '.'
DECLARE @keysValueToSearchPattern NVARCHAR(4000) = '%' + @keysValueToSearch + '%'
--Nothing to touch here
SELECT SUBSTRING(
@a,
PATINDEX(@keysValueToSearchPattern, @a) + LEN(@keysValueToSearch),
CHARINDEX(
@untilThisCharAppears,
@a,
PATINDEX(@keysValueToSearchPattern, @a) + LEN(@keysValueToSearch)
) -(PATINDEX(@keysValueToSearchPattern, @a) + LEN(@keysValueToSearch))
)
Solution 6:[6]
I just did this in one of my reports and it was very simple.
Try this:
=MID(Fields!.Value,8,4)
Note: This worked for me because the value I was trying to get was a constant not sure it what you are trying to get is a constant as well.
Solution 7:[7]
I know this has been a while.. but here is an idea
declare @test varchar(25) = 'images/test.jpg'
select
@test as column_name
, parsename(replace(@test,'/','.'),1) as jpg
,parsename(replace(@test,'/','.'),2) as test
,parsename(replace(@test,'/','.'),3) as images
Solution 8:[8]
SELECT Substring('[email protected]', 1, ( Charindex('@', '[email protected]')
- 1 ))
Before,
RIGHT('[email protected]', ( Charindex('@', '[email protected]') + 1 ))
After
Solution 9:[9]
I found Royi Namir's answer useful but expanded upon it to create it as a function. I renamed the variables to what made sense to me but you can translate them back easily enough, if desired.
Also, the code in Royi's answer already handled the case where the character being searched from does not exist (it starts from the beginning of the string), but I wanted to also handle cases where the character that is being searched to does not exist.
In that case it acts in a similar manner by starting from the searched from character and returning the rest of the characters to the end of the string.
CREATE FUNCTION [dbo].[getValueBetweenTwoStrings](@inputString
NVARCHAR(4000), @stringToSearchFrom NVARCHAR(4000), @stringToSearchTo
NVARCHAR(4000))
RETURNS NVARCHAR(4000)
AS
BEGIN
DECLARE @retVal NVARCHAR(4000)
DECLARE @stringToSearchFromSearchPattern NVARCHAR(4000) = '%' +
@stringToSearchFrom + '%'
SELECT @retVal = SUBSTRING (
@inputString,
PATINDEX(@stringToSearchFromSearchPattern, @inputString) + LEN(@stringToSearchFrom),
(CASE
CHARINDEX(
@stringToSearchTo,
@inputString,
PATINDEX(@stringToSearchFromSearchPattern, @inputString) + LEN(@stringToSearchFrom))
WHEN
0
THEN
LEN(@inputString) + 1
ELSE
CHARINDEX(
@stringToSearchTo,
@inputString,
PATINDEX(@stringToSearchFromSearchPattern, @inputString) + LEN(@stringToSearchFrom))
END) - (PATINDEX(@stringToSearchFromSearchPattern, @inputString) + LEN(@stringToSearchFrom))
)
RETURN @retVal
END
Usage:
SELECT dbo.getValueBetweenTwoStrings('images/test.jpg','/','.') AS MyResult
Solution 10:[10]
You can try this:
Declare @test varchar(100)='images/test.jpg'
Select REPLACE(RIGHT(@test,charindex('/',reverse(@test))-1),'.jpg','')
Solution 11:[11]
Below query gives you data before '-' Ex- W12345A-4S
SELECT SUBSTRING(Column_Name,0, CHARINDEX('-',Column_Name)) as 'new_name'
from [abc].
Output - W12345A
Solution 12:[12]
Inspired by the work of Josien, I wondered about a simplification.
Would this also work? Much shorter:
SELECT SUBSTRING(col, CHARINDEX ('/', col) + 1, CHARINDEX ('.', col) - CHARINDEX ('/', col) - 1);
(I can't test right now because of right issues at my company SQL server, which is a problem in its own right)
Solution 13:[13]
Simply Try With LEFT ,RIGHT ,CHARINDEX
select
LEFT((RIGHT(a.name,((CHARINDEX('/', name))+1))),((CHARINDEX('.', (RIGHT(a.name,
((CHARINDEX('/', name))+1)))))-1)) splitstring,
a.name
from
(select 'images/test.jpg' as name)a
Solution 14:[14]
I got some invalid length errors. So i made this function, this should not give any length problems. Also when you do not find the searched text it will return a NULL.
CREATE FUNCTION [FN].[SearchTextGetBetweenStartAndStop](@string varchar(max),@SearchStringToStart varchar(max),@SearchStringToStop varchar(max))
RETURNS varchar(max)
BEGIN
SET @string = CASE
WHEN CHARINDEX(@SearchStringToStart,@string) = 0
OR CHARINDEX(@SearchStringToStop,RIGHT(@string,LEN(@string) - CHARINDEX(@SearchStringToStart,@string) + 1 - LEN(@SearchStringToStart))) = 0
THEN NULL
ELSE SUBSTRING(@string
,CHARINDEX(@SearchStringToStart,@string) + LEN(@SearchStringToStart) + 1
,(CHARINDEX(@SearchStringToStop,RIGHT(@string,LEN(@string) - CHARINDEX(@SearchStringToStart,@string) + 1 - LEN(@SearchStringToStart)))-2)
)
END
RETURN @string
END
Solution 15:[15]
declare @searchStart nvarchar(100) = 'search ';
declare @searchEnd nvarchar(100) = ' ';
declare @string nvarchar(4000) = 'This is a string to search (hello) in this text ';
declare @startIndex int = CHARINDEX(@searchStart, @string,0) + LEN(@searchStart);
declare @endIndex int = CHARINDEX(@searchEnd, @string, @startIndex + 1);
declare @length int = @endIndex - @startIndex;
declare @sub nvarchar(4000) = SUBSTRING(@string, @startIndex, @length)
select @startIndex, @endIndex, @length, @sub
This is a little more legible than the one-liners in this answer which specifically answer the question, but not in a generic way that would benefit all readers. This could easily be made into a function as well with a slight modification.
Solution 16:[16]
If there are more than one or none occurences of given character use this:
DECLARE @rightidx int = CASE
WHEN 'images/images/test.jpg' IS NULL OR (CHARINDEX('.', 'images/images/test.jpg')) <= 0 THEN LEN('images/images/test.jpg')
ELSE (CHARINDEX('.', REVERSE('images/images/test.jpg')) - 1)
END
SELECT RIGHT('images/images/test.jpg', @rightidx)
Solution 17:[17]
This was the approach I took.
CREATE FUNCTION dbo.get_text_before_char(@my_string nvarchar(255),@my_char char(1))
RETURNS nvarchar(255)
AS
BEGIN;
return IIF(@my_string LIKE '%' + @my_char + '%',left (@my_string, IIF(charindex(@my_char, @my_string) - 1<1,1,charindex(@my_char, @my_string) - 1)),'');
END;
CREATE FUNCTION dbo.get_text_after_char(@my_string nvarchar(255),@my_char char(1))
RETURNS nvarchar(255)
AS
BEGIN;
return IIF ( @my_string LIKE '%' + @my_char + '%' ,RIGHT ( @my_string , IIF ( charindex ( @my_char ,reverse(@my_string) )-1 < 1 ,1 ,charindex ( @my_char ,reverse(@my_string) )-1 ) ) , '' )
END;
SELECT
dbo.get_text_before_char('foo-bar','-')
, dbo.get_text_after_char('foo-bar','-')
Solution 18:[18]
if Input= pg102a-wlc01s.png.intel.com and Output should be pg102a-wlc01s
we can use below query :
select Substring(pc.name,0,charindex('.',pc.name,0)),pc.name from tbl_name pc
Solution 19:[19]
declare @test varchar(100)='images/test.jpg'
select right(left(@test, charindex('.', @test) - 1),4)
Sources
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