Get current superclass (or constructor) in JavaScript

Question

In JavaScript (ES6), how do I programmatically get the name of the super class, in which the "current" code is executed?

Example:

class MySuperClass {
   logName() {
     console.log(this.XXX()); // always logs "MySuperClass"
   }
}

class MySubClass extends MySuperClass {
   logName() {
      super.logName();
      console.log(this.XXX()); // always logs "MySubClass"
   }
}

class MySubSubClass extends MySubClass {
   logName() {
      super.logName();
      console.log(this.XXX()); // always logs "MySubSubClass"
   }
}

const subSubClass = new MySubSubClass();

console.log(subSubClass);

Expected result from this code would be:

MySuperClass
MySubClass
MySubSubClass

What do I need to do instead of this.XXX()?

Note that I do not want to hard-code the name of the classes as string constants. I want a way that gets the "current" class name programmatically, as the flow trickles up the class tree.

Possible?

What does NOT work is this.constructor.name - it always returns the "lowest" inherited constructor name, in this case, it would yield "MySubSubClass" in all 3 levels.

Edit: One kind of hacky way would be to throw an exception on purpose and parse the stack string to see in which file / class the exception was thrown. But ugh! Is there no clean way?