'forEach vs for in: Different Behavior When Calling a Method

I noticed that forEach and for in to produce different behavior. I have a list of RegExp and want to run hasMatch on each one. When iterating through the list using forEach, hasMatch never returns true. However, if I use for in, hasMatch returns true.

Sample code:

class Foo {
  final str = "Hello";
  final regexes = [new RegExp(r"(\w+)")];

  String a() {
    regexes.forEach((RegExp reg) {
      if (reg.hasMatch(str)) {
        return 'match';
      }
    });
    return 'no match';
  }

  String b() {
    for (RegExp reg in regexes) {
      if (reg.hasMatch(str)) {
        return 'match';
      }
    }
    return 'no match';
  }
}

void main() {
  Foo foo = new Foo();
  print(foo.a()); // prints "no match"
  print(foo.b()); // prints "match"
}

(DartPad with the above sample code)

The only difference between the methods a and b is that a uses forEach and b uses for in, yet they produce different results. Why is this?



Solution 1:[1]

Although there is a prefer_foreach lint, that recommendation is specifically for cases where you can use it with a tear-off (a reference to an existing function). Effective Dart recommends against using Iterable.forEach with anything else, and there is a corresponding avoid_function_literals_in_foreach_calls lint to enforce it.

Except for those simple cases where the callback is a tear-off, Iterable.forEach is not any simpler than using a basic and more general for loop. There are more pitfalls using Iterable.forEach, and this is one of them.

  • Iterable.forEach is a function that takes a callback as an argument. Iterable.forEach is not a control structure, and the callback is an ordinary function. You therefore cannot use break to stop iterating early or use continue to skip to the next iteration.

  • A return statement in the callback returns from the callback, and the return value is ignored. The caller of Iterable.forEach will never receive the returned value and will never have an opportunity to propagate it. For example, in:

    bool f(List<int> list) {
      for (var i in list) {
        if (i == 42) {
          return true;
        }
      }
      return false;
    }
    

    the return true statement returns from the function f and stops iteration. In contrast, with forEach:

    bool g(List<int> list) {
      list.forEach((i) {
        if (i == 42) {
          return true;
        }
      });
      return false;
    }
    

    the return true statement returns from only the callback. The function g will not return until it completes all iterations and reaches the return false statement at the end. This perhaps is clearer as:

    bool callback(int i) {
      if (i == 42) {
        return true;
      }
    }
    
    bool g(List<int> list) {
      list.forEach(callback);
      return false;
    }
    

    which makes it more obvious that:

    1. There is no way for callback to cause g to return true.
    2. callback does not return a value along all paths.

    (That's the problem you encountered.)

  • Iterable.forEach must not be used with asynchronous callbacks. Because any value returned by the callback is ignored, asynchronous callbacks can never be waited upon.

I should also point out that if you enable Dart's new null-safety features, which enable stricter type-checking, your forEach code will generate an error because it returns a value in a callback that is expected to have a void return value.

A notable case where Iterable.forEach can be simpler than a regular for loop is if the object you're iterating over might be null:

List<int>? nullableList;
nullableList?.forEach((e) => ...);

whereas a regular for loop would require an additional if check or doing:

List<int>? nullableList;
for (var e in nullableList ?? []) {
  ...
}

(In JavaScript, for-in has unintuitive pitfalls, so Array.forEach often is recommended instead. Perhaps that's why a lot of people seem to be conditioned to use a .forEach method over a built-in language construct. However, Dart does not share those pitfalls with JavaScript.)

Sources

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Source: Stack Overflow

Solution Source
Solution 1