'For Loop to Rename Column Names of Many Objects R

I am looking for a way to rename the columns of several objects with a for loop or other method in R. Ultimately, I want to be able to bind the rows of each Stock object into one large data frame, but cannot due to differing column names. Example below:

AAPL <-
Date        AAPL.Open  AAPL.High AAPL.Low  AAPL.Close  AAPL.Volume  AAPL.Adjusted  Stock  pct_change
2020-05-14  304.51     309.79    301.53    309.54      39732300     309.54         AAPL   0.61
2020-05-15  300.35     307.90    300.21    307.71      41561200     307.71         AAPL  -0.59


GOOG <-  
Date        GOOG.Open GOOG.High  GOOG.Low  GOOG.Close  GOOG.Volume   GOOG.Adjusted  Stock  pct_change 
2020-05-14  1335.02   1357.420   1323.910  1356.13     1603100       1356.13        GOOG   0.50
2020-05-15  1350.00   1374.480   1339.000  1373.19     1705700       1373.19        GOOG   1.26

For this example I have 2 objects (AAPL and GOOG), but realistically I would be working with many more. Can I create a for loop to iterate through each object, and rename the 2nd column of each to "Open", 3rd column to "High", 4th column to "Low",.... etc so I can then bind all these objects together?

I already have a column named "Stock", so I do not need the Ticker part of the column name.



Solution 1:[1]

If you can guarantee the order of these columns this should do it:

for(df in list(AAPL, GOOG))
  colnames(df) <- c("Date", "Open", "High", "Low", "Close", "Volume", "Adjusted", "Stock", "pct_change")

Solution 2:[2]

With lapply, we can loop over the list and remove the prefix in the column names with sub. This can be done without any external packages

lst1 <- lapply(list(AAPL, GOOG),  function(x)  {
        colnames(x) <- sub(".*\\.", "", colnames(x))
    x})

Sources

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Source: Stack Overflow

Solution Source
Solution 1 Jan
Solution 2