Finding child element of parent with JavaScript

Question

What would the most efficient method be to find a child element of (with class or ID) of a particular parent element using pure javascript only. No jQuery or other frameworks.

In this case, I would need to find child1 or child2 of parent, assuming that the DOM tree could have multiple child1 or child2 class elements in the tree. I only want the elements of parent

<div class="parent">
    <div class="child1">
        <div class="child2">
        </div>
    </div>
</div>

Answer 1

If you already have var parent = document.querySelector('.parent'); you can do this to scope the search to parent's children:

parent.querySelector('.child')

Answer 2

Just adding another idea you could use a child selector to get immediate children

document.querySelectorAll(".parent > .child1");

should return all the immediate children with class .child1

Answer 3

Element.querySelector() is the best way;

const parent = document.querySelector('.parent'); 
// Do anything next //When you want
parent.querySelector('.child1'); // <div class="child1">

Answer 4

You have a parent element, you want to get all child of specific attribute 1. get the parent 2. get the parent nodename by using parent.nodeName.toLowerCase() convert the nodename to lower case e.g DIV will be div 3. for further specific purpose, get an attribute of the parent e.g parent.getAttribute("id"). this will give you id of the parent 4. Then use document.QuerySelectorAll(paret.nodeName.toLowerCase()+"#"_parent.getAttribute("id")+" input " ); if you want input children of the parent node

let parent = document.querySelector("div.classnameofthediv")
let parent_node = parent.nodeName.toLowerCase()
let parent_clas_arr = parent.getAttribute("class").split(" ");
let parent_clas_str = '';
  parent_clas_arr.forEach(e=>{
     parent_clas_str +=e+'.';
  })
let parent_class_name = parent_clas_str.substr(0, parent_clas_str.length-1)  //remove the last dot
let allchild = document.querySelectorAll(parent_node+"."+parent_class_name+" input")