Explaining the 'find -mtime' command

Question

I'm trying to remove all the dateed logs except the most recent. Before I execute a script to remove the files, I want to of course test my commands to make sure I'm bringing up accurate results.

When executing these commands the date is:

Sep  1 00:53:44 AST 2014

Directory Listing:

Aug 27 23:59 testfile.2014-08-27.log
Aug 28 23:59 testfile.2014-08-28.log
Aug 29 23:59 testfile.2014-08-29.log
Aug 30 23:59 testfile.2014-08-30.log
Aug 31 23:59 testfile.2014-08-31.log
Sep  1 00:29 testfile.log

I thought -mtime +1 was supposed to list all files over a day old. Why isn't the 8-30.log one listed?

find . -type f -mtime +1 -name "testfile*log"
./testfile.2014-08-27.log
./testfile.2014-08-28.log
./testfile.2014-08-29.log

This is the desired effect, but it was just trial and error. What is this 0 saying?

find . -type f -mtime +0 -name "testfile*log"
./testfile.2014-08-30.log
./testfile.2014-08-27.log
./testfile.2014-08-28.log
./testfile.2014-08-29.log

Answer 1

+1 means 2 days ago. It's rounded.

Answer 2

To find all files modified in the last 24 hours use the one below. The -1 here means changed 1 day or less ago.

find . -mtime -1 -ls

Answer 3

#{user} is user-name
#name of script is 'place.{user}'
#used manually or from cron
#moves files that are created by automated job queue at night 
 for the user and identified by find into dated 
 subdirectories in user's home directory, so moves them 
 from"
 /u/home/{user} to /u/home/{user}/2022/05/05 on the 5th of 
 May in 2022.

cd /u/home/{user}/
place=`date '+./%Y/%m/%d/'`;
find ./*.csv -mtime -.6 -exec mv {} $place \;
find ./*.txt -mtime -.6 -exec mv {} $place \;
find ./*.tab -mtime -.6 -exec mv {} $place \;
find ./*.pdf -mtime -.6 -exec mv {} $place \;
cd $place
chmod 666 ./*
chown {user} ./*
chgrp users ./*