'Exectue function every one hour in Python

I wanted to execute a program every once hour. I can use time.sleep function to delay the interval but, if the program executed let's say at 16:30 then the function will only execute at 17:30. But I need to execute the function at 17:00, 18:00 and so on.

import datetime

def onehour(value):
   print "%d Hours" % value

now = datetime.datetime.now()
oncehour(now.hour)
python-2.7


Solution 1:[1]

You need to sleep first, if current time is 12:23, then you need to sleep 60-23 = 37 minutes and then run your code every hour.
Here you can write like this:

import time
import datetime

time.sleep(60 * (60 - datetime.datetime.now().minute))
while True:
    do_smth()
    sleep(60 * 60)

Solution 2:[2]

What about Cron jobs ? You can write your code inside a Python file then call it from command line inside your crontab:

0 * * * * python script.py

Sources

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Source: Stack Overflow

Solution Source
Solution 1
Solution 2 Saksow

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