'(Duplicated) C++ Classes set/get from base and derived class [duplicate]
I want to create a base class with two set, and derived class (inherit) with one set method. I want to combine them in a parameterized constructor.
#include <iostream>
#include <string.h>
using namespace std;
class Code
{
protected:
string letter;
int number;
public:
string getletter();
int getnumber();
void setletter(string letter1);
void setnumber(int number1);
};
void Code::setletter(string letter1)
{
letter=letter1;
}
void Code::setnumber(int number1)
{
number=number1;
}
string Code::getletter()
{
return letter;
}
int Code::getnumber()
{
return number;
}
class Course : public Code
{
private:
string name;
public:
Course(string name1, string letter1, int number1);
string getname();
void show();
};
Course::Course (string name1, string letter1,int number1) :
setletter(letter1), setnumber(number1) //Parameterized Constructor
{
name=name1;
letter=letter1;
number=number1;
}
string Course::getname()
{
return name;
}
void show()
{
Course com("Testing","TST",101);
cout<<"Constructor >>>\n Course Name : "<< com.getname()<<"\n Course Code : "<< com.getletter() << com.getnumber()<<endl;
}
int main()
{
show();
}
If it matters, I am using Microsoft's Visual C++.
Solution 1:[1]
You can call them inside your constructor
Course::Course (const string& name1, const string& letter1, const int number1) :
{
name=name;
setletter(letter1); // equivalent to letter=letter1
setnumber(number1);
}
You can add a constructor to your Code class
Code(const string& letter, const int number);
And call it like that in your Course constructor
Course::Course(const string& name1, const string& letter1, const int number1)
: Code(letter1, number1), name(name1)
{
}
But I'm not sure of what your asking, if you can be a little more precise on what you want that could be great, thanks.
Solution 2:[2]
The : after the parameter list of a constructor is the 'member initializer list'.
Course::Course (string name1, string letter1,int number1)
: name(name1), letter(letter1), number(number1) { }
Sources
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Source: Stack Overflow
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