'docker mongo for single (primary node only) replica set (for development)?
This is the portion of the dockerfile that has served us well to date. However, now I need to convert this to be a single node replica set (for transactions to work). I don't want any secondary or arbiter - just the primary node. What am I missing to get this working?
mongo:
image: mongo:4.4.3
container_name: mongo
restart: unless-stopped
environment:
MONGO_INITDB_ROOT_USERNAME: root
MONGO_INITDB_ROOT_PASSWORD: myPass
command: mongod --port 27017
ports:
- '27017:27017'
volumes:
- ./data/mongodb:/data/db
- ./data/mongodb/home:/home/mongodb/
- ./configs/mongodb/mongo-init.sh:/docker-entrypoint-initdb.d/mongo-init.sh:ro
Solution 1:[1]
Got it working. I inserted the following into the block in my question above:
hostname: mongodb
volumes:
- ./data/mongodb/data/log/:/var/log/mongodb/
# the healthcheck avoids the need to initiate the replica set
healthcheck:
test: test $$(echo "rs.initiate().ok || rs.status().ok" | mongo -u root -p imagiaRoot --quiet) -eq 1
interval: 10s
start_period: 30s
Solution 2:[2]
I was unable to initiate the replica set via the healthcheck. I used the bash script below instead. For Windows users, be sure to call your DB with the name of your computer. For example:
mongodb://DESKTOP-QPRKMN2:27017
run-test.sh
#!/bin/bash
echo "Running docker-compose"
docker-compose up -d
echo "Waiting for DB to initialize"
sleep 10
echo "Initiating DB"
docker exec mongo_container mongo --eval "rs.initiate();"
echo "Running tests"
# test result
if go test ./... -v
then
echo "Test PASSED"
else
echo "Test FAILED"
fi
# cleanup
docker-compose -f docker-compose.test.yml down
docker-compose file
version: '3.8'
services:
mongo:
hostname: $HOST
container_name: mongo_container
image: mongo:5.0.3
volumes:
- ./test-db.d
expose:
- 27017
ports:
- "27017:27017"
restart: always
command: ["--replSet", "test", "--bind_ip_all"]
This forum post was very helpful: https://www.mongodb.com/community/forums/t/docker-compose-replicasets-getaddrinfo-enotfound/14301/4
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Mike |
| Solution 2 |
