Django: URL Path not found jumps into next app

Question

I have two apps:

backend shop

I my urls in main app dir:

path('backend/', include('backend.urls')),
path('', include('shop.urls')),

the problem is if I write in my url: localhost:8000/backend/abc which not exist Django jumps over to shop.urls and the app is crashing because it can not find the slug and the query goes in fail.

How can I prevent if I go to the url /backend/somethingwhichnotexist is returning an 404 and not search in other app urls for this folder? I have thought that this is one of the main reason for split the urls in app folders.

Here are some urls from backend/urls.py:

from django.urls import path, re_path
from . import views as backend_views
from django.contrib.auth import views as auth_views
from froala_editor import views
from django.conf.urls import include
urlpatterns = [
path('stamdata/', backend_views.edit_masterdata),
path('praefikser/', backend_views.edit_prefixes),
path('leverandorer/', backend_views.suppliers_view),
path('leverandorer/add', backend_views.add_supplier),

]

handler404 = 'backend.views.page_not_found_view'

shop/urls.py

here the url stops:

path('<slug:category_slug>/<slug:slug_subcategory>/', butik_views.cat_or_article),

normally I don't want that a backend urls switches to frontend view

regards Christopher.

Answer 1

You you said Django run through all of the URL patterns and stops till it finds its matching URL. SO, what has happen here is that when you type a URL with localhost:8000/backend/abc/ it runs through all the URLS before returning 404 to the client. So, it stops at the URL that support any string with 2 parameters in your case below URL.

path('<slug:category_slug>/<slug:slug_subcategory>/', butik_views.cat_or_article),

To get a 404 by adding a static word in you URL.

path('shop/<slug:category_slug>/<slug:slug_subcategory>/', butik_views.cat_or_article),

or

path('backend/', include('backend.urls')),
path('shop/', include('shop.urls')),