Delete all files older than 30 days, based on file name as date

Question

I'm new to bash, I have a task to delete all files older than 30 days, I can figure this out based on the files name Y_M_D.ext 2019_04_30.txt.

I know I can list all files with ls in a the folder containing the files. I know I can get todays date with $ date and can configure that to match the file format $ date "+%Y_%m_%d"

I know I can delete files using rm.

How do I tie all this together into a bash script that deletes files older than 30 days from today?

In pseudo-python code I guess it would look like:

for file in folder:
    if file.name to date > 30 day from now:
        delete file

Answer 1

Here is another solution to delete log files older than 30 days:

#!/bin/sh

# A table that contains the path of directories to clean
rep_log=("/etc/var/log" "/test/nginx/log")
echo "Cleaning logs - $(date)."

#loop for each path provided by rep_log 
for element in "${rep_log[@]}"
do
   #display the directory
    echo "$element";
    nb_log=$(find "$element" -type f -mtime +30 -name "*.log*"| wc -l)
    if [[ $nb_log != 0 ]] 
    then
            find "$element" -type f -mtime +30 -delete 
            echo "Successfull!"
    else
            echo "No log to clean !"
    fi
done

allows to include multiple directory where to delete files

rep_log=("/etc/var/log" "/test/nginx/log")

we fill the var: we'r doing a search (in the directory provided) for files which are older than 30 days and whose name contains at least .log. Then counts the number of files.

nb_log=$(find "$element" -type f -mtime +30 -name "*.log*"| wc -l)

we then check if there is a result other than 0 (posisitive), if yes we delete

find "$element" -type f -mtime +30 -delete

Answer 2

For delete file older than X days you can use this command and schedule it in /etc/crontab

find /PATH/TO/LOG/* -mtime +10 | xargs -d '\n' rm

or

find /PATH/TO/LOG/* -type f -mtime +10 -exec rm -f {} \