Declaring a variable type from std::type_info

Question

Can I declare variable type just from std::type_info? I would like to do something like this:

void some_function(std::type_info type){
    type variable;
}

Is it possible to give it as the parameter to the function and initialize it in it?

Answer 1

I'm sure this is incorrect C++ since the type in the function declaraition is a variable name, and the type in the function body is a type name. Those can not be interchanged.

(Note: I'm deducing this by pure logic and some knowledge of C++. Other users will most probably add some information about std::type_info itself.)