'Count cycles in a permutated list
I am trying to make a function that counts the number of cycles within a permutated list.
I do sometimes get the right answer when running the code, but most times I receive an error message - and I am unable to figure out why.
My code is as follows:
def count_cycles(n):
cycle_count = 0
copy_list = []
for element in n:
copy_list.append(element)
while len(copy_list) != 0:
ran_num = random.choice(copy_list)
while True:
if n[ran_num] == ran_num:
cycle_count = circle_count + 1
if int(ran_num) in copy_list:
copy_list.remove(ran_num)
break
else:
n.insert(ran_num, ran_num)
print(n, ran_num, copy_list)
ran_num = n[ran_num + 1]
print(ran_num)
copy_list.remove(ran_num)
n.remove(ran_num)
continue
return print(cycle_count, n)
What I use is that I test with this permutated list with 3 cycles [2, 6, 0, 3, 1, 4, 5].
Picture of output from a correct and incorrect run
I used print(n, ran_num, copy_list) to assess the output as per the picture.
Solution 1:[1]
In addition to the existing answer, sympy provides some functionality to work with permutations. In this case, you could use the following:
from sympy.combinatorics import Permutation
p = Permutation([2, 6, 0, 3, 1, 4, 5])
num_cycles = p.cycles # 3
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | hilberts_drinking_problem |
