Convert multi-arrow function into an-line call

Question

Is it possible to convert the following to an in-line expression?

const
    rePlace = (count) => (m) => {
        count ++;
        return (parseInt(m) > 255 || count > 4) ? '<invalid>' : m;
    },
    regex = /\d+(?=(\.|$))/g,
    potential_ips = ['1.2.3.4.5', '12.34.45.56', '123.456.789.0', '1.2.3.4.5.6'];  
for (let ip of potential_ips) {
    ip = ip.replace(regex, rePlace(0));
    console.log(ip);
}

My first attempt was to call the function with (0) as a parameter, but I think on successive calls it fails:

regex = /\d+(?=(\.|$))/g;
potential_ips = ['1.2.3.4.5', '12.34.45.56', '123.456.789.0', '1.2.3.4.5.6'] ;  
for (let ip of potential_ips) {
    ip = ip.replace(regex, ((count) => (m) => count++, (parseInt(m) > 255 || count > 4) ? '<invalid>' : m)(0));
    console.log(ip);
}

Is there a way to do this, or not possible?

Answer 1

Here's the original, but with traditional function functions:

const
    rePlace = function(count) {
        return function(segment) {
          count ++;
          return (parseInt(segment) > 255 || count > 4) ? '<invalid>' : segment;
        };
    },
    regex = /\d+(?=(\.|$))/g,
    potential_ips = ['1.2.3.4.5', '12.34.45.56', '123.456.789.0', '1.2.3.4.5.6']; 
    
for (let ip of potential_ips) {
    ip = ip.replace(regex, rePlace(0));
    console.log(ip);
}

It might be a little clearer expressed that way.