Checking for multiple conditions with JavaScript includes() method inside filter() method

Question

I am trying to filter out words that include zz or ZZ but can't quite get it to work. I am trying to use includes() within the filter() method. I'm not sure if the || operand is the correct choice here.

function removeZZ (str){
  let splitStr = str.split(" ")
  let noBuzz = splitStr.filter(word => !word.includes("zz") ||!word.includes("ZZ") )
  return noBuzz.join(" ")
}

Answer 1

You can use word.toLowerCase().includes

const str = "wed zzAA ZZSS 34f34f"

function removeZZ(str) {
  return str
    .split(" ")
    .filter(word => !word.toLowerCase().includes("zz"))
    .join(" ");
}
console.log(removeZZ(str))

With your approach you need to use && instead of ||

const str = "wed zzAA ZZSS 34f34f"

function removeZZ(str) {
  let splitStr = str.split(" ")
  let noBuzz = splitStr.filter(word => !word.includes("zz") && !word.includes("ZZ"))
  return noBuzz.join(" ")


}
console.log(removeZZ(str))

Answer 2

Or simply you can make each word lowercase and check if it includes 'zz'. Try the following example.

function removeZZ (str){
  let splitStr = str.split(" ")
  let noBuzz = splitStr.filter(word => !word.toLowercase().include('zz'))
  return noBuzz.join(" ")
}

Answer 3

Your logic is a bit inverted by using the || instead of && operator.

Instead you could write this:

let noBuzz = splitStr.filter(word => !word.includes("zz") && !word.includes("ZZ") )

Or use an Array of blocked words instead:

let noBuzz = splitStr.filter(word => !["zz", "ZZ"].includes(word))

Or, as they are the same and only the case is different, try a Regex:

let noBuzz = splitStr.filter(word => !word.match(/zz/i))

Answer 4

Here is code , hope it will help you. Your First error is you are not returning anything from filter method. Second error is in or (||) condition. You have to use and (&&) condition for checking both conditions if word not contains 'zz' and 'ZZ'.

function removeZZ (str){
  let splitStr = str.split(" ")
  let noBuzz = splitStr.filter(word =>{
   
    if(!word.includes("zz") && !word.includes("ZZ")){
      return word;
    }
   })
  return noBuzz.join(" ")
}

const ans=removeZZ("zz asoaZZzz aos as ZZAas Azz");
console.log("ans is : ",ans)