'Check if a character is lowerCase or upperCase
I am trying to make a program that stores a string in a variable called input.
With this input variable, I am then trying to convert it to an array, and then test with a for loop whether each character in the array is lowerCase or not. How can I achieve this?
Here is how far I have gotten:
var input = "The quick BroWn fOX jumpS Over tHe lazY DOg"
var inputArray = Array(input)
for character in inputArray {
/*
if character is lower case {
make it uppercase
} else {
make it lowercase
}
*/
}
Solution 1:[1]
Swift 3
static func isLowercase(string: String) -> Bool {
let set = CharacterSet.lowercaseLetters
if let scala = UnicodeScalar(string) {
return set.contains(scala)
} else {
return false
}
}
Solution 2:[2]
Swift 4:
var input = "The quick BroWn fOX jumpS Over tHe lazY DOg"
let uppers = CharacterSet.uppercaseLetters
let lowers = CharacterSet.lowercaseLetters
input.unicodeScalars.forEach {
if uppers.contains($0) {
print("upper: \($0)")
} else if lowers.contains($0) {
print("lower: \($0)")
}
}
Solution 3:[3]
If I had to, I'd probably code something like this:
extension Character {
func isMember(of set: CharacterSet) -> Bool {
guard let scalar = UnicodeScalar(String(self)) else { return false }
return set.contains(scalar)
}
var isUppercase: Bool {
return isMember(of: .uppercaseLetters)
}
// var isLowercase, isWhitespace, etc.
}
let result = "The quick BroWn fOX jumpS Over tHe lazY DOg"
.map { $0.isUppercase ? String($0).lowercased() : String($0).uppercased() }
.joined()
print(result)
// "tHE QUICK bROwN Fox JUMPs oVER ThE LAZy doG"
Solution 4:[4]
You should use regexp: grep [A-Z] versus grep [a-z].
Solution 5:[5]
Here's an answer written on Swift 4 that works wether the input String is a single or multiple letters:
extension String {
static func isLowercase(string: String) -> Bool {
let set = CharacterSet.lowercaseLetters
for character in string {
if let scala = UnicodeScalar(String(character)) {
if !set.contains(scala) {
return false
}
}
}
return true
}
static func isUppercase(string: String) -> Bool {
let set = CharacterSet.uppercaseLetters
for character in string {
if let scala = UnicodeScalar(String(character)) {
if !set.contains(scala) {
return false
}
}
}
return true
}
}
Solution 6:[6]
A solution based on character comparison
let input = "The quick BroWn fOX jumpS Over tHe lazY DOg"
for char in input {
if char >= "A" && char <= "Z" {
print("upper: \(char)")
} else if char >= "a" && char <= "z" {
print("lower: \(char)")
} else {
print("something else: '\(char)'")
}
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | onmyway133 |
| Solution 2 | Andrew Tetlaw |
| Solution 3 | |
| Solution 4 | aaaaa says reinstate Monica |
| Solution 5 | Juan Carlos Ospina Gonzalez |
| Solution 6 | ArunGJ |
