'Check if a character is lowerCase or upperCase

I am trying to make a program that stores a string in a variable called input.

With this input variable, I am then trying to convert it to an array, and then test with a for loop whether each character in the array is lowerCase or not. How can I achieve this?

Here is how far I have gotten:

var input = "The quick BroWn fOX jumpS Over tHe lazY DOg"

var inputArray = Array(input)

for character in inputArray {
    /*

    if character is lower case {

        make it uppercase

    } else {

        make it lowercase

    }

    */
}


Solution 1:[1]

Swift 3

static func isLowercase(string: String) -> Bool {
    let set = CharacterSet.lowercaseLetters

    if let scala = UnicodeScalar(string) {
      return set.contains(scala)
    } else {
      return false
    }
  }

Solution 2:[2]

Swift 4:

var input = "The quick BroWn fOX jumpS Over tHe lazY DOg"
let uppers = CharacterSet.uppercaseLetters
let lowers = CharacterSet.lowercaseLetters
input.unicodeScalars.forEach {
    if uppers.contains($0) {
        print("upper: \($0)")
    } else if lowers.contains($0) {
        print("lower: \($0)")
    }
}

Solution 3:[3]

If I had to, I'd probably code something like this:

extension Character {
    func isMember(of set: CharacterSet) -> Bool {
        guard let scalar = UnicodeScalar(String(self)) else { return false }
        return set.contains(scalar)
    }
    var isUppercase: Bool {
        return isMember(of: .uppercaseLetters)
    }
    // var isLowercase, isWhitespace, etc.
}

let result = "The quick BroWn fOX jumpS Over tHe lazY DOg"
    .map { $0.isUppercase ? String($0).lowercased() : String($0).uppercased() }
    .joined()
print(result)

// "tHE QUICK bROwN Fox JUMPs oVER ThE LAZy doG"

Solution 4:[4]

You should use regexp: grep [A-Z] versus grep [a-z].

Solution 5:[5]

Here's an answer written on Swift 4 that works wether the input String is a single or multiple letters:

  extension String {
      static func isLowercase(string: String) -> Bool {
          let set = CharacterSet.lowercaseLetters
          for character in string {
              if let scala = UnicodeScalar(String(character)) {
                  if !set.contains(scala) {
                      return false
                  }
              }
          }
          return true
      }

      static func isUppercase(string: String) -> Bool {
          let set = CharacterSet.uppercaseLetters
          for character in string {
              if let scala = UnicodeScalar(String(character)) {
                  if !set.contains(scala) {
                      return false
                  }
              }
          }
          return true
      }
  }

Solution 6:[6]

A solution based on character comparison

let input = "The quick BroWn fOX jumpS Over tHe lazY DOg"

for char in input {
    if char >= "A" && char <= "Z" {
        print("upper: \(char)")
    } else if char >= "a" && char <= "z" {
        print("lower: \(char)")
    } else {
        print("something else: '\(char)'")
    }
}

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 onmyway133
Solution 2 Andrew Tetlaw
Solution 3
Solution 4 aaaaa says reinstate Monica
Solution 5 Juan Carlos Ospina Gonzalez
Solution 6 ArunGJ