I want to calculate the mean for the second index for each third index. @njit def mean_some_index(a): T = a.shape[2] b = np.zeros((T,T)) for t in ra
I am using numba cuda to calculate a function. The code is simply to add up all the values into one result, but numba cuda gives me a different result from nu
I try to use the Numba for some fast calculations. I got the following issue while creating a package that use a Numba extension. I did similar things as sugges
Numba Cuda has syncthreads() to sync all thread within a block. How can I sync all blocks in a grid without exiting the current kernel? In C-Cuda there's a coo