Category "list"

how can I remove some NA rows but not all of them

I have multiple data frames with information about listed companies from the year 2000 So I want to put them in a list (lets call it df) because I want to do re

words amalgamation

I am new user learning python. I have query if it can be done or not. If user input a word suppose "Dance" and characters are "$" and "@", he would get a all po

displaying parent-child elements hierarchically in c#

I have a parent-child structure in my db and I want to list them hierarchically n a C# program: id text parentid 1 A NULL 2 B NULL 5 a1 1 6

How to move an Item inside a list of lists?

I have the following list of lists representing a matrix stored in space: [' ', '1', '1', ' '] [' ', '1', ' ', ' '] [' ', '1', ' ', ' '] [' ', ' ', ' ', ' '] T

How do I efficiently find which elements of a list are in another list?

I want to know which elements of list_1 are in list_2. I need the output as an ordered list of booleans. But I want to avoid for loops, because both lists have

Java 8 Streams - How to get an equivalent of partitioningBy() with Integer keys?

In the code shown below, p is a predicate of type Predicate<String>. Map<Boolean, List<String>> partitioned = numbers.stream() .collect(Co

Two ways of slicing Python nested lists

I have following code mylst is a nested list: mylst = [[507, 3, 30, 44, 522, 25], [268, 40, 23, 54, 280, 67], [424, 37, 28, 50, 438, 62], [216, 47, 24, 50, 22

Return keys from nested dictionary Python

I have a nested dictionary as such: {'needed1': {'notneeded': {'needed2': 'some_value'}, 'notneeded2': {'needed2': 'some_value'}, 'notneeded3': {'needed3: '

What determines the item order when converting a set to a list?

I know there are several similar questions, but I haven't found one yet that talks about what I would like to know. If this is a duplicate, please point it out.

How to extract tensors to numpy arrays or lists from a larger pytorch tensor

I have a list of pytorch tensors as shown below: data = [[tensor([0, 0, 0]), tensor([1, 2, 3])], [tensor([0, 0, 0]), tensor([4, 5, 6])]] Now this is ju

Resultset To List null [duplicate]

public List<Order> getAllOrdersByCustomerId(int customerId) throws SQLException { List<Order> AllOrdersByCustomerId = new Arra

Counting valid passwords in a list

I have a list passwords = ['baCr', '/)T.I]DdLNh)^WRIDa_z1', 'izM!Imi', 'NOb5VEhw$[17Q{P', 'i',

Custom Button in SwiftUI List

SwiftUI Custom Button in List I'm trying to create a custom button in a SwiftUI List. I want it to have a blue background with white text, and importantly, to

Find a individual word location in a list that isn't its own value

I am trying to find a specific word in a list. As simple as it sounds, me and the people I've talked to can't think of an answer. Below is an example of my issu

how to pull certain data from a list response from instagrapi

so I'm working on some code to pull the pictures of people who have liked a post on instagram. i'm using instagrapi for the api system, but when using api.media

how to convert the dictionary string to dictionary int?

A = {'1': '[1,2]', '2': '[3,4]', '3': '[5,6]', '4': '[7,8]', '5': '[9,10]' } B = {'1': '70', '2': '70', '3': '70', '4': '70', '5': '70' } How to convert this m

Python Count Letters in Word

I am looking to complete this code but cannot get it to execute the right way. The program connects two user-inputted names into one full name and then looks fo

Unable to assign the result returned by the Method that receives a generic List and returns a List<?>

I'm trying to filter a List of objects that implements an interface. And I'm trying to create a generic method for all the classes. Something like: interface So

IndexError: list index out of range in for loop

I write a code in python but I faced this error : if a1[i] == a1[i+1] == a1[i+2]: IndexError: list index out of range I write an if condition that if my list l

Convert this String to a List in Python

I'm new to Python and I try to convert following txt to two lists, splitting Country from Capital. Afghanistan | Kabul Albania | Tirana Algeria | Algiers ... I