urls.py -> ''''from django.contrib import admin from django.urls import path from Administrator import views admin.site.index_template = 'admi
The Django docs show how to return the last page of a paginated queryset using a function-based view by catching the EmptyPage exception. What's the easiest wa
I am developing an application (simple online store) with Python Django I have created a base.html file in templates and then all other html files extends from
I have created child ('Bid') model related to a parent(Post) model in my Django project. I also created a BidForm which I have added in my B_Bid.view so that ty
am Getting this error i cant figure a way to solve it here are the views.py class SellerTransactionListView(ListView): model = Transaction template_na