c++ passing a pointer to a template function as template

Question

I have this iter function that takes a pointer to value_type, a size_type, and a function pointer fun_type that is supposed to take a value_type& as parameter:

template <
    class value_type,
    class size_type,
    class fun_type
> void  iter(value_type *arr, size_type size, fun_type function)
{ while (size--) function(arr[size]); }

It works fine until we have a function that has a template, let's say for example we want to use this function:

template <
   class T
> void print(const T &value) { std::cout << value << std::endl; }

Then we get this compilation error:

main.cpp:35:1: error: no matching function for call to 'iter'
iter( tab, 5, print );
^~~~
./iter.hpp:17:8: note: candidate template ignored: couldn't infer template argument 'fun_type'
> void  iter(value_type *arr, size_type size, fun_type function)
        ^
main.cpp:36:1: error: no matching function for call to 'iter'
iter( tab2, 5, print );
^~~~
./iter.hpp:17:8: note: candidate template ignored: couldn't infer template argument 'fun_type'
> void  iter(value_type *arr, size_type size, fun_type function)

How could I make fun_type work with every function no matter the template and the return type of the function?